Conical Pendulum Period — Does It Ever Match a Simple Pendulum of the Same Length?
Conical Pendulum: How the Cone Angle Sets Period, Tension and Speed
The string’s pull does two jobs. Its vertical part holds the bob up: FT cos β = mg. Its horizontal part is the whole net force, pointing at the center of the circle: FT sin β = mv2/r. Divide one by the other and the mass cancels: tan β = v2/(gr), so ac = g tan β. Mass never appears in β, T, v, ac or r; it only scales the tension.
Wider cone, faster orbit, shorter period. With r = ℓ sin β and T = 2π√(ℓ cos β ÷ g), opening the cone widens the circle yet shortens T: v climbs without limit while T falls toward zero. A heavy bob and a light one on the same string at the same angle take exactly the same time per revolution.
Why 90° is impossible. As β nears 90°, cos β nears 0, so FT = mg ÷ cos β grows without limit: a level string has no vertical part left to hold up the weight. Watch FT ÷ mg in the readout: it reaches 2 at 60°, and at 85°, where this sim stops, the tension is about 11.5 times the weight.
Does a conical pendulum ever have the same period as a simple pendulum of the same length?
In short: Only in the limit of a vanishing cone angle. A conical pendulum has period T = 2π√(ℓ cos β ÷ g). Because cos β is less than 1 for any open cone, T is always a little shorter than the small-swing simple pendulum value 2π√(ℓ/g), and widening the cone shortens it further.
Common doubts
- “Does a heavier bob change the period?” No. Mass cancels out of tan β = v²/(gr). A heavy and a light bob on the same string at the same angle take exactly the same time per revolution. Mass only scales the tension.
- “Why does a wider cone give a shorter period?” The circle gets wider, r = ℓ sin β, but the bob moves faster by more than enough to make up for it, so T falls while v climbs.
- “Why can the string never be horizontal?” The vertical part of the tension must hold up the weight: FT cos β = mg. As β nears 90°, cos β nears 0, so FT = mg ÷ cos β grows without limit.
Change the cone angle, string length and mass in the simulation above and watch T, v and the tension respond.
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